Anyone Good at Math

[Del Delaplante]

Need a formula.
Hit a ball with a 10* driver.
The shot travels 300 yards (flight only, assume the ball hits and digs in).
What would be the height of the ball at the 1/2 point.
What would be the height of the ball at the 200 yard mark.
Any assistance would be muchly appreciated....

[Pingnut]

I don't think there will be only one answer to this question.
Depends on a quite a number of variables.

[owenmxz600]

1 + 3 beers = 4

[nearace]

1 + 3 beers = 4thats after 5 holes i assume?

[owenmxz600]

thats b4 we start....

[mikejb]

10* does not represent the launch angle, it would represent the face angle.

You would need to know the launch angle. I would then assume you would need to also know the following. How fast is the ball traveling, how fast is the ball spinning. Is there any wind etc.

[nearace]

thats b4 we start....wheres the pic for that one (drunk homer)would be good

[dan_]

Give us the launch angle, not the driver angle. I think it's possible to solve if we have that information.

[corchard]

Need a formula.
Hit a ball with a 10* driver.
The shot travels 300 yards (flight only, assume the ball hits and digs in).
What would be the height of the ball at the 1/2 point.
What would be the height of the ball at the 200 yard mark.
Any assistance would be muchly appreciated....

No easy answer. ball spin, clubhead speed, Launch angle...

Here is a good summary. (assuming you passed Grade 12 physics)

http://www.probablegolfinstruction.com/science_golf_ball_flight.htm


Where is peter G when you need him :p

[Louie]

wheres the pic for that one (drunk homer)would be good




Nearace he probibly has one.:D

[The Bun]

Need a formula.
Hit a ball with a 10* driver.
The shot travels 300 yards (flight only, assume the ball hits and digs in).
What would be the height of the ball at the 1/2 point.
What would be the height of the ball at the 200 yard mark.
Any assistance would be muchly appreciated....

I know one thing. "If your aunt had balls she'd be your uncle." :p

-Bun-:beer:cheers brother

[leftintherough]

10* does not represent the launch angle, it would represent the face angle.

You would need to know the launch angle. I would then assume you would need to also know the following. How fast is the ball traveling, how fast is the ball spinning. Is there any wind etc.

Also, I think elevation from sea level, outdoor temperature, barametric pressure, and relative humidity would also be factors in the model.

[wayland]

1 + 3 beers = 4

BZZZZT!!! W R O N G

1+3 beers = start of a good time...


Del, the 10* loft of the driver doesn't mean anything because your swing can deloft it or add more loft depending on angle of attack, etc.

[owenmxz600]

I know one thing. "If your aunt had balls she'd be your uncle." :p

-Bun-:beer:cheers brother

I LOVE IT http://i44.photobucket.com/albums/f13/ehw092678/homer_simpson_beer.jpg

[Bellyhungry]

Need a formula.
Hit a ball with a 10* driver.
The shot travels 300 yards (flight only, assume the ball hits and digs in).
What would be the height of the ball at the 1/2 point.
What would be the height of the ball at the 200 yard mark.
Any assistance would be muchly appreciated....

- If you use Pro V, the 1/2 height is 30 ft
- If you use Pro V*, the 1/2 height is 20 ft
- If you simply drop the ball from a 300 yards high vertical cliff, the 1/2 height is exactly 150 yards
- If you are Tiger Woods with his stinger, the 1/2 height is 5 ft off the ground
- If you are Michelle Wie, your 300-yard drive is in your dream
- If this is someone you meet on the local muni, his '300-yard' drive is more like 300 feet
- If your name is Angel Cabrera or Jimenez, your driver has an illegal COR
- If you can hit your 3 iron 300 yards, you live next door to the tooth fairy and Santa Claus

[Del Delaplante]

Thanks Corchard that gives me a starting point. Did not appreciate all the varialbles involved, especially the 3 beers, angle of the dangle and all the others.... thanks again...

[DubRepublic]

36 = 0
34 = -2
38 = +2

That's how golfers do Calculus.

[klink1983]

All you need to solve this is actual givens etc. etc. and then solve as for the pythagorean theorem. (Triangle)

I dont want to do it because the cooling system for my brain wont keep up.

[Bellyhungry]

All you need to solve this is actual givens etc. etc. and then solve as for the pythagorean theorem. (Triangle)

I dont want to do it because the cooling system for my brain wont keep up.

Pythagorean theorem's optimal angle is 45 degree. In drivers, launch angles seldom exceed 15 degree....:cool:

[nearace]

http://www.mlangenstein.de/gifs/homer_pool.gif


:embarasse

[golfinseb]

the shape of the flight of the ball would take some advanced calculus (sp?) to describe as a function. It's not really even uniform in any way, has alot to do with the spin on teh ball. In general the ball starts low, than climbs higher and finally drops quickly.

Of course this is in an ideal world, as we all know there are many different ball flights that can be generated (and often are). I don't know how you can get the numbers you want, but I'd sure like to know how to stop the dreaded hook and or slice from appearing in my game.

[Louie]

http://www.mlangenstein.de/gifs/homer_pool.gif


:embarasse

Nice pic Howie. That reminds of the Bun right after work in the summer.

[owenmxz600]

that IS bun right after work in the summer!

[Del Delaplante]

The answer to the problem given the few variables I gave would be 29.8 yards height at the half way point..... thanks again Corchard the guy that runs that site figured it out for me..... does driving ranges .......

[bilinguru]

The motion of an object under the influence of gravity is determined completely by the acceleration of gravity, its launch speed, and launch angle provided air friction is negligible. The horizontal and vertical motions may be separated and described by the general motion equations (http://hyperphysics.phy-astr.gsu.edu/hbase/mot.html#mot1) for constant acceleration. The initial vector components of the velocity are used in the equations. The diagram shows trajectories with the same launch speed but different launch angles. Note that the 60 and 30 degree trajectories have the same range, as do any pair of launches at complementary angles. The launch at 45 degrees gives the maximum range. http://hyperphysics.phy-astr.gsu.edu/hbase/imgmec/tra12.gif

The question begging here is why do you want to know? How will this knowledge help your game? If you are just curious, that's cool. But, I can't see how knowing the height of your drives is going to help you get more distance, let alone lower your score.

Link for the above sit is
http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html

Have fun!

[golfinseb]

thats not correct in terms of describing the flight of a gold ball. The shape of the ball flight is not uniform as in the model provided. That's where spin, launch angle and initial velocity come into play.


We have expensive launch monitors because optimizing ball flight is not so easy as suggested.

[Del Delaplante]

Thanks very much for the info Bilinguru, I guess I should have been honest about what I wanted the info for.... I'm thinking about building a golf training/driving range, and I'm trying to keep the costs down. I wanted to know if it was possible to get away with a 200 yard driving area, with a catch net. I wanted to know how high a ball would be in the air at the 200 yard mark if it was hit 300 yards, so that I could see if it was a practical height for a catch net. I want to build a site more for practing the short game, but a very accurate 200 yard layout, distances +/- yard or so. Additional distances could be scaled up the catch net....Was'nt trying to get away with a freebie, just needed to know someone who could do the math for me... Again thanks for the info.....

[Chambokl]

You better have an iron only rule at your driving range. Your net will never be high enough for drivers or other woods (even hybrid). Unless you have really high post...

What Belinguru has here is useless for a golf ball. Liek a few people mention the golf ball starts low and then with the spin gets more altitude and then will drop...

What BG showed you is a parabola with perfect condition (no spin).

Seb is totally right.

[Del Delaplante]

Kinda wondered about the high take off angles. There's an Exec-par three in Markham, with a driving range, they have a catch net about 210, 60 foot poles and very few balls make it over the net.

[Chambokl]

Our driving range at the golf course is kinda design the same way. About 210 yrds with netting all around. There is a house about 100+ yrds behind the driving range and some guys would hit the house.

2 years ago they decided it would be irons only... They would lose too many balls.

Some people just drive too far (not me)

Good luck.

Chambo

[jjgowland]

He probably wants to know because of the advice of some pros is "Hit it high, let it fly."

I figure if the ball is going TOO high, it isn't going to roll at all, but will dig into the perfect fairway like a power drill on speed.

[Golf2Relax]

I found a simulator by googling on "golf ball path":

http://www.ecs.syr.edu/centers/simfluid/red/golf.html

(classy avatar Chom)